Question

Find the area of each figure. When an answer is NOT a whole number, round to the nearest tenth. Show work and explain answer in order for the medal to be received for personage.

Answer 1

You can use pythagorean theorem where c is 24.

since both sides are equal a =b

a^2 + a^2 = c^2

Answer 2

could I use x instead of a & b

Answer 3

sure, why not. Proceed:
c=24
\[x^2+ x^2 = c^2\]

Answer 4

x = 12 times the sqrt 2

Answer 5

is that answer the base or the height

Answer 6

not exactly. PEDMAS.

Either way the whole point of the problem is they're both the same length sides

Answer 7

that is a square right?

Answer 8

yes

Answer 9

the diagonal of a square is equal to the length of the side times \(\sqrt{2}\)
so the length of the side is equal to the diagonal of the square divided by \(\sqrt2\)

Answer 10

How would that look?

Answer 11

like this
\[a=\frac{d}{\sqrt{2}}\]

Answer 12

Area = 1/2bh

Answer 13

not for a square
the area of a square with side \(a\) is \(a^2\)
that is why you read \(a^2\) as "a squared"

Answer 14

A = 24 over sqrt of 2

Answer 15

\(a=\frac{24}{\sqrt{2}}\) so
\[A=\left(\frac{24}{\sqrt2}\right)^2\]

Answer 16

A = 288ft^2

Answer 17

i dont know i didn't do it but it looks good
you get \(\frac{24^2}{2}\) whatever that is

Answer 18

yeah you are right

Answer 19

divide 24 over sqrt 2 first to get 16.97056275 then take 16.97..^2 to get 288 --> 288ft^2

Answer 20

better to square 24, then divide by 2

Answer 21

either way works