Question

So I was given the following incomplete nuclear equation: 210 83 Bi→ ?+4 2He
I'm sorry, I can't really write that any better, but hopefully you can visualize the 210 on the top and the 83 on the bottom.

Anyways, my answer for the ? was the isotope: 206 81 Ti

But, my program marked it as wrong... What's the problem?

Answer 1

Hmmm lets see what I get:
This is a α-decay so
\[\Large \sf _{83}^{210}Bi ~ \to ~ _{2}^{4}He ~ + ~ _{81}^{206}Ti\]
That should be correct what you say.
It follows the rules of conservation.

Answer 2

I've vent over it in the following \(\sf \large \href{study#/updates/52616b4de4b0c23cd54ac96f}{post}\)
(press to enter link)