Complex Equation |x + iy| = y - ix
ok so i get that it will split up into: y = |x| and -x = |y| right? so \[y \ge 0\]
but then our book says that x=0?
Your book is quite right :)
...listen up... this part on the left... (which I thoughtfully coloured in blue) is going to be a plain-and-simple real number, right? (And a positive one, at that) Because it's an ABSOLUTE VALUE (or modulus, si vous preferez) \[\Large \color{blue}{|x+iy|}=y - ix\] ...right? ^_^
yah
:)
Well then, that forces the RIGHT side of the equation (which I thoughtfully coloured in red) to also be a plain-and-simple real number: \[\Large |x+iy|= \color{red}{y-ix}\]
And if the right-side is a pure real number, then x MUST be zero, otherwise, it would have an imaginary component, which basically spells the end of the world, all right? :3
hrm
why does it have to be 0 though?
if it isn't, then the right-side gains an imaginary part...
Which is impossible, because, it is equal to the absolute value of something, which may NEVER have an imaginary part.
Get it? It's just as absurd as having an absolute value equal to some negative number, say |z| = -5 It simply isn't possible ^_^
@ksmith197 Do you understand now? ^_^
hey sorry off doing other stuff :o um yah well logically i understand what you are saying. you can't have an absolute value equal to an imaginary number
so the only value it can equal is 0
but how do you write that as a solution?
More or less... more like you can't have an absolute value with an imaginary part.
couldn't you do a transformation of it though? z= x + iy
ooo i think that may be it. we have other problems that are similar, where z= x + iy = sqrt( x^2 + y^2)
eliminating the i
something like that, still, it all boils down to the fact that the left side has NO imaginary part, and therefore, so must the right-side. Makes sense, yeah?
yah that makes sense. thank you very much :) :)
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