A 20 kg cart is moving at 2.0 m/s when a 5.0 N force is applied for a distance of 6.0 m in the direction the car is moving. What is the kinetic energy of the cart at the end of the 6.0 m?

Question

anonymous · Answer

@undeadknight26 ? Any chance you could help me out? :)

undeadknight26 · Answer

o.o
I learned this stuff a while ago so i don;t really member it...

anonymous · Answer

Oh that's too bad :/  Any idea who might know? Someone else I could ask...?

anonymous · Answer

@Loser66 ? Is there any chance you know how to do this...?

anonymous · Answer

Or @wolfe8 ?

anonymous · Answer

I'm assuming it's just 1/2 * 20 * 2.0^2

loser66 · Answer

you have to find out V by $ V^2 = V_0^2 + 2as$  to get Velocity.
to find a , you need apply F = ma where F = 5.0N , m = 20kg
after then, put all into kinetic energy formula K.E = 1/2 mv ^2

anonymous · Answer

So a = 25

What is s? seconds?

anonymous · Answer

*0.25

loser66 · Answer

s is the length it moves = 6.0 m

anonymous · Answer

2.0^2 + 3 = V^2 ?

anonymous · Answer

V^2 = 7?

loser66 · Answer

yup

anonymous · Answer

So 70 J would be my answer

anonymous · Answer

Great! Could you help me with one more? (I'll start a new thread)