Part C: Another object moves in the air along the path of g(t) = 31 + 32.2t where g(t) is the height, in feet, of the object from the ground at time t seconds. Use a table to find the approximate solution to the equation H(t) = g(t) and explain what the solution represents in the context of the problem? H(t)=-16t^2 + 80t + 96 g(t) = 31 + 32.2t
I really need help
i'm not sure about the table but if you want, you can solve it algebraically to find the solutions H(t) = g(t) \(-16t^2 + 80t + 96 = 31 + 32.2t \) \(-16t^2 + 80t - 32.2t + 96 - 31=0\) \(-16t^2 + 47.8t + 65=0\) then use the quadratic formula to solve for the values of t \(\Large t=\frac{ -b \pm \sqrt{b^2-4ac} }{2a}\) where a=-16, b=47.8, c=65
I got -.83 and .14 is that right?
Do H(t) and g(t) intersect when the projectile is going up or down and how do you know?
they will intersect at two points, since there's a solution when you set H(t)=g(t) and for the the value of "t" i got a different answer t is approximately 4.002 and -1.015
sorry late response, i'm away from my keyboard awhile ago
so where will they intersect?
when H(t)=G(t) which means that the values for "t" that you just found out
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