Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (andijo76):

if i post a statistics question can anyone answer it

OpenStudy (anonymous):

I suppose that would depend on what the question was.

OpenStudy (andijo76):

i will post it and you tell me

OpenStudy (anonymous):

sounds like a plan

OpenStudy (andijo76):

a certain brand of candies have a mean weight of 0.8604g and a standard deviation of o.052 based on a sample of a package conatining 441 candies the package label stated that the net weight is 376. 5 g (if every package has 441 candies the mean wieght of the candies must exceed 376.5/441 = 0.8537 for the net contents to weigh 441 at least 376.5g if 1 candy is randomly selected find the probability that it weighs more than 0.8537g or greater is

OpenStudy (anonymous):

Well, you could calculate the z-score of the desired weight \[ Z = \frac{0.8537 - 0.8604}{0.052} \] since 0.8604 g is the sample mean and 0.052 g is the sample standard deviation Then you would use a z-score chart to find the area to the right of that particular value in your bell curve.

OpenStudy (andijo76):

crap there is more there is a part b

OpenStudy (anonymous):

And what might that be?

OpenStudy (andijo76):

if 441 candies are randomly selected find the probability that their mean of 0.8537g or greater is

OpenStudy (andijo76):

okay for the first part i came up with .5478

OpenStudy (anonymous):

That seems about right

OpenStudy (anonymous):

For the second part, you do essentially the same calculation but for the standard deviation you would use 0.052 / sqrt(441). That value is called the standard error of the mean.

OpenStudy (andijo76):

oh okay i will try it out

OpenStudy (andijo76):

i will show you to make sure we are on the same page i sorta understand it

OpenStudy (anonymous):

Okay

OpenStudy (andijo76):

i might seem like a moron but i dont think i am putting it in right

OpenStudy (anonymous):

How are you calculating the z-score?

OpenStudy (andijo76):

i was trying it this way but its wrong \[\frac{ 0.052 }{ \sqrt{441}}\]

OpenStudy (anonymous):

No, you do (0.8537-0.8506)/ (0.052 / sqrt(441) )

OpenStudy (andijo76):

2.1?

OpenStudy (andijo76):

i got twenty one do i move the decimal one over

OpenStudy (anonymous):

Doing that calculation gives me -2.7

OpenStudy (andijo76):

i must have missed a number or typed it wrong lol

OpenStudy (anonymous):

so you would then use the z-score chart to find the probability that z > -2.7. It should be very high.

OpenStudy (andijo76):

i know thats why i figured i was doing something wrong

OpenStudy (andijo76):

.9956 is my answer

OpenStudy (andijo76):

2.7 i looked at and the 00

OpenStudy (anonymous):

That looks about right.

OpenStudy (andijo76):

thank you sooooooo much i appreciate it you were such a big help all i have is one more and then i am done :) thank you again

OpenStudy (anonymous):

No problem

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!