A cyclist is travelling along a straight road. The (t,v) graph above, where t is measured in seconds and v is measured in vms^-1, consists of three line segments and models the first 250m/s of the cylists journey. The cyclist has a constant speed of Vms^-1 in the interval 60

Question

A cyclist is travelling along a straight road. The (t,v) graph above, where t is measured in seconds and v is measured in vms^-1, consists of three line segments and models the first 250m/s of the cylists journey. The cyclist has a constant speed of Vms^-1 in the interval 60<or equal to t< or equal to 160
a) find an expression in terms of v for the distance travelled in meters in first 200 seconds 
b) given that the average speed of the cylcist in the interval 0< or equal to t or < or equal to 200 is 6.75ms^-1 find V
c) Hence find the distance of the cylist from his starting point at the

abmon98 · Answer

end of the 250 seconds

abmon98 · Answer

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abmon98 · Answer

i solved a and b 
im stucks in c

abmon98 · Answer

stuck**

ganeshie8 · Answer

a) find an expression in terms of v for the distance travelled in meters in first 200 seconds

ganeshie8 · Answer

|dw:1392386308892:dw|

ganeshie8 · Answer

a) 

distance = area under velocity curve

$\large     d =   \frac{1}{2}60V + 100V + \frac{1}{2}40V$

ganeshie8 · Answer

b) given that the average speed of the cylcist in the interval 0< or equal to t or < or equal to 200 is 6.75ms^-1 find V

$\large  200*6.75=   \frac{1}{2}60V + 100V + \frac{1}{2}40V $

solve $V$

abmon98 · Answer

V=9

ganeshie8 · Answer

yes i see ur work is looking good :)

abmon98 · Answer

part c is too hard i cant figure out the v in time =250

ganeshie8 · Answer

from part b, we knw that
he travelled 200*6.75 = 1350 meters in first 200 seconds

ganeshie8 · Answer

we just need to find out, how much distance he travelled between 200 and 250 seconds
right ?

abmon98 · Answer

yes