What is the general form of the equation of a circle with its center at (-2,1) and passing through (-4,1)?

x^2 + y^2+4x-2y+1=0

x^2 + y^2+4x-2y+9=0

x^2 - y^2+2x+y+1=0

Question

What is the general form of the equation of a circle with its center at (-2,1) and passing through (-4,1)?

x^2 + y^2+4x-2y+1=0

x^2 + y^2+4x-2y+9=0

x^2 - y^2+2x+y+1=0

anonymous · Answer

$$
(x+2)^2+(y-1)^2=r^2
$$
We still have to fine $ r^2$.

anonymous · Answer

The distance from the center to a point on the circle is r and hence r=2

anonymous · Answer

$$
(x+2)^2+(y-1)^2=4\
4 + 4 x + x^2  + y^2-2 y+1=4\

x^2+4 x+y^2-2 y+5=4\
x^2+4 x+y^2-2 y+1=0
$$

anonymous · Answer

im confused

anonymous · Answer

so just saw your new post

anonymous · Answer

It is the first choice

anonymous · Answer

Did you understand it?

anonymous · Answer

i just fiquired out it is the 1st choice.
x^2 + y^2+4x-2y+1=0
this might kill me.
can you check my answer on another one?

anonymous · Answer

Post is as new problem and tag me

anonymous · Answer

ok thanks i can't open it up foer some reasom issues with open study

anonymous · Answer

You have to close this one and open a new one

anonymous · Answer

See the picture