Question

What is the general form of the equation of the given circle with center A.
A (-3,12)
Radius 5

x^2+y^2+6x-24y-25=0

Answer 1

@eliassaab

Answer 2

You forgot some squares

Answer 3

\[
3^2 + 12^2
\]

Answer 4

ok thinking :/

Answer 5

\[
(x+3)^2+(y-12)^2=
x^2+6 x+y^2-24y+153\\
\]
Hence
\[
x^2+6 x+y^2-24y+153=25\\
x^2+6 x+y^2-24y+128=0
\]

Answer 6

\[
3^2 + 12^2 = 9+ 144=153
\]

Answer 7

x^2+y^2+6x-24y+148=0
I did something wrong

Answer 8

yes, you did something wrong
153-25=128

Answer 9

x^2+y^2+6x-24y+128=0

Answer 10

\[
(x+3)^2 = x^2+ 6x +9\\
(y-12)^2=y^2 -24 y + 144\\
x^2+6 x+y^2-24
y+153=25\\
x^2+6 x+y^2-24
y+128=0\\
\]

Answer 11

thank you!!!!!

Answer 12

YW