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WILL GIVE MEDAL!!! Using the given zero, find one other zero of f(x). Explain the process you used to find your solution. 1 - 6i is a zero of f(x) = x4 - 2x3 + 38x2 - 2x + 37.
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If a - ib is a zero then a+ib is a zero
So 1+ 6i is a zero
Here are the four roots (i, -i, 1+ 6i, 1-6i)
Is that everytime though?
Yes, when the polynomial has rational coefficients
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That makes sense. Thank you!
YW
\[ x^4 - 2 x^3 + 38 x^2 - 2 x + 37 = (1 + x^2) (37 - 2 x + x^2)=0 \] When you use the quadratic formula, then\[x= something \pm i \quad somethingelse\]
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