Question

A father's age is one less than twice that of his son, and the digits making up the father's age are reversed in the son's age. Find the age of both the father and the son

Answer 1

The digits MN making up the father's age are reversed in the son's age i.e NM --> F=10M+N and S=10N+M (notice that M and N must be digits: 0, 1, 2, ..., 9) --> (10M+N)+1=2*(10N+M) --> 8M=19N-1. Only one set of digits satisfy this equation: M=7 and N=3 (by trial and error: 19N-1 is even and also a multiple of 8 --> N must odd --> so try N=1 and N=3 to see whether 19N-1 is a multiple of 8. For N>=5, M>10 so not a solution for M as it must be a single digit integer) --> S=10N+M=37 and F=73.

Answer 2

Its all in the wording. Father is 1 less than twice of son, so in other words twice of son is 1 more than fathe

Answer 3

r

Answer 4

makes sense?

Answer 5

Say son's age is 37, then father's is 73 (1 less than twice. )

Answer 6

so the father is 73 and the son is 37