Question

4x^3+2x^2-8x/2x

Answer 1

\[\frac{ 4x^3+2x^2-8x }{ 2x } simplify\]

Answer 2

\(\bf \cfrac{4x^3+2x^2-8x}{2x}\implies \cfrac{4x^3}{2x}+\cfrac{2x^2}{2x}-\cfrac{8x}{2x}\)

Answer 3

ok and what makes it more simplified

Answer 4

\[4x^2+2x^2-8\] ????????

Answer 5

@jdoe0001

Answer 6

@Abmon98

Answer 7

is it power 2 or 3

Answer 8

2

Answer 9

i think 2

Answer 10

2x not 2x^2 sorry bout that

Answer 11

is the answer o was trying to put

Answer 12

can you can cancel anything from each fraction?

Answer 13

what you mean what answer you get?

Answer 14

6x^2-8=(x+2(3)^1/2/3))(x-2(3)^1/2/3)
(3x+2(3)^1/2)(3x-2(3)^1/2)

Answer 15

\[4x^2+2x-8 \] was my answer but not sure

Answer 16

anyone???

Answer 17

\(\bf \cfrac{4x^3+2x^2-8x}{2x}\implies \cfrac{4x^3}{2x}+\cfrac{2x^2}{2x}-\cfrac{8x}{2x}\\ \quad \\\implies \cfrac{2x^2}{1}\cdot +\cancel{\cfrac{2x}{2x}}\cdot \cancel{\cfrac{2x}{2x}}-\cfrac{4}{1}\cdot \cancel{\cfrac{2x}{2x}}\)

Answer 18

hmm lemme fix that... some

Answer 19

2x^2+x-4 ????

Answer 20

???????????

Answer 21

\(\bf \cfrac{4x^3+2x^2-8x}{2x}\implies \cfrac{4x^3}{2x}+\cfrac{2x^2}{2x}-\cfrac{8x}{2x}\\ \quad \\
\implies \cfrac{2x^2}{1}\cdot \cancel{\cfrac{2x}{2x}}+\cfrac{x}{1}\cdot \cancel{\cfrac{2x}{2x}}-\cfrac{4}{1}\cdot \cancel{\cfrac{2x}{2x}}\)

Answer 22

2x^2+x-4 ???? \(\huge \checkmark\)

Answer 23

kk