Daniel is using logarithms to solve the equation 24x = 14. Which of the following equations would be equivalent to his original expression?
These are the choices 2 log 4x = log 14 4x log 2 = log 14 2 log 4 = x log 14 x log 4 = 2 log 14
The original equation is \[\Large 2^{4x} = 14\] right?
Yes
@Isaih.Feynman?
Take the log of both sides. Then use rule 3 on this page http://www.purplemath.com/modules/logrules.htm to get \[\Large \log(2^{4x}) = \log(14)\] \[\Large 4x\log(2) = \log(14)\]
Thank you for helping jim
Thank you so very much Jim! I was so desperate for that answer. I am taking a 50 question test and that was the only one I was missing! I just made this account and I don't know how to give medals or anything, but thank you!
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