Segment AB has point A located at (5, 4). If the distance from A to B is 7 units, which of the following is the coordinate for point B? (5 points) Select one: a. (3, 2) b. (-2, 4) c. (2, 1) d. (12, 11)
@MelissaHolmes @jim_thompson5910
hi!
helo can you help me on this one to
ya, sure
whoa... profile picture change there.... XD
yea
d. because... (5, 4) 5 + 7 = 12 4 + 7 = 11 thus... (12, 11)
@iambatman do agree
Hint: use the distance formula \[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]
soooo.... was i right? i never learned anything about a formula....
(x1,y1) = (5,4) (x2,y2) = (x,y) d = 7 so... \[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\] \[\Large 7 = \sqrt{\left(x-5\right)^2+\left(y-4\right)^2}\]
so you would multiply out the squared stuff and solve for x and y?
Now let's see if (12,11) is 7 units away from point A. Plug in (x,y) = (12,11) \[\Large 7 = \sqrt{\left(x-5\right)^2+\left(y-4\right)^2}\] \[\Large 7 = \sqrt{\left(12-5\right)^2+\left(11-4\right)^2}\] \[\Large 7 = \sqrt{\left(7\right)^2+\left(7\right)^2}\] \[\Large 7 = \sqrt{49+49}\] \[\Large 7 = \sqrt{98}\] \[\Large 7 = 9.89949493\] So because that last equation is false, this means that (12,11) is NOT 7 units away from point A
hmm... so how would you find out what the actual answer is?
plug in each point and see which satisfy the equation \[\Large 7 = \sqrt{\left(x-5\right)^2+\left(y-4\right)^2}\]
oh.... so no way to actually solve?
what should i go with
unfortunately no because there are infinitely many points that are 7 units away from A
if we could replace y with some expression in terms of x, then we can solve
hmmm.... i see..... ok
ok then ill get to the next one then ok
so we each do one?
ok im about to post it here
Two boats start their journey from the same point A and travel along directions AC and AD, as shown below.
What is the distance, CD, between the boats? (5 points) Select one: a. 461.9 ft b. 530.9 ft c. 646.4 ft d. 325.5 ft
@jim_thompson5910 do u know this?
yes, it turns out that B is the answer because... \[\Large 7 = \sqrt{\left(x-5\right)^2+\left(y-4\right)^2}\] \[\Large 7 = \sqrt{\left(-2-5\right)^2+\left(4-4\right)^2}\] \[\Large 7 = \sqrt{\left(-7\right)^2+\left(0\right)^2}\] \[\Large 7 = \sqrt{49+0}\] \[\Large 7 = \sqrt{49}\] \[\Large 7 = 7\] So (-2,4) is one point that is 7 units away from A(5,4)
is 5,4 the answer
hmm... ok :D
ok what about this one
good job @jim_thompson5910 you are very knowledgeable :D
i just posted
hint: first find the lengths of BC and BD to get CD, you subtract, so CD = BD - BC
you will use the idea that \[\Large \tan(\theta) = \frac{\text{opp}}{\text{adj}}\]
so what would it be @jim_thompson5910
are you able to find BC or BD?
NO i was thinking it was A but maybe im wrong
I'll show you how to find BC \[\Large \tan(\theta) = \frac{\text{opp}}{\text{adj}}\] \[\Large \tan(60) = \frac{400}{BC}\] \[\Large BC\tan(60) = 400\] \[\Large BC = \frac{400}{\tan(60)}\]
i have three more questions after thi one ok
actually four hope you guys can help you really have been good to me
1, 249.842 is what i got. but that doesn't seem right... @jim_thompson5910 ?
oh, and sure @prowrestler i'll help the best i can :D
Finding BD \[\Large \tan(\theta) = \frac{\text{opp}}{\text{adj}}\] \[\Large \tan(30) = \frac{400}{BD}\] \[\Large BD\tan(30) = 400\] \[\Large BD = \frac{400}{\tan(30)}\]
Now subtract \[\Large CD = BD - BC\] \[\Large CD = \frac{400}{\tan(30)} - \frac{400}{\tan(60)}\] \[\Large CD \approx 461.8802153517 ... \ \text{Use a calculator here}\]
So the answer is A
for that last line, you type in "400/tan(30) - 400/tan(60)" without quotes
If you do not have a calculator, google is a great calculator Just type in "400/tan(30 degrees) - 400/tan(60 degrees)" without quotes into google to get https://www.google.com/search?q=400/tan(30%20degrees)%20-%20400/tan(60%20degrees)
my calculator came out with -1, 312.290?????
you need to be in degree mode MelissaHolmes
aahhhh... ok i see.... that makes sense.....
So the answer is A right
and google by default is in radian mode, so you have to tack on the word "degrees" in each tangent to force degree mode in google
yes prowrestler
thanks
couple more guys and gals
ok!
Find the perimeter of a quadrilateral with vertices at C (-2, 1), D (2, 4), E (5, 0), and F (1, -3). Round your answer to the nearest hundredth when necessary. (5 points) Select one: a. 12 units b. 16 units c. 20 units d. 24 units
@jim_thompson5910
ummm.... this is completely new to me.... sorry...... :( maybe post it as a new question and see if anyone else can help u...
I want to see if @jim_thompson5910 can help hes smart
and you are to:)
i know, he IS smart... he's helping someone else currently apparently
oh, and thanks!
stay here though please
ok :)
@campbell_st
Find the perimeter of a quadrilateral with vertices at C (-2, 1), D (2, 4), E (5, 0), and F (1, -3). Round your answer to the nearest hundredth when necessary. (5 points) Select one: a. 12 units b. 16 units c. 20 units d. 24 units
oh, u know what... i'll graph the points and try to figure it out and be helpful :D
ok
i love you for this
@jim_thompson5910 can you help now:)
ok so i graphed this and i got this:
hey fan me back and give me a medal pleeease:)
so maybe around 24 units?
sure!
can i have a medal to
medal?
thanks
:D
what do you look like
@jim_thompson5910 heres the question
Find the perimeter of a quadrilateral with vertices at C (-2, 1), D (2, 4), E (5, 0), and F (1, -3). Round your answer to the nearest hundredth when necessary. (5 points) Select one: a. 12 units b. 16 units c. 20 units d. 24 units
MelissaHolmes it looks like you used geogebra to plot those points. You can use geogebra to calculate the distances/lengths and find the perimeter.
we thought it was 24 units
i can? and yeah... i did use geogebra...
see attached
whoa.... okay... i guess you can.....
A segment with endpoints A (3, 4) and C (5, 11) is partitioned by a point B such that AB and BC form a 2:3 ratio. Find B. (5 points) Select one: a. (3.8, 6.8) b. (3.9, 4.8) c. (4.2, 5.6) d. (4.3, 5.9)
it's possible you just didn't have the "algebra" window open to see the segment lengths
ok.... maybe...
oh, yeah that makes sense :D
@jim_thompson5910 can u help?
A (3, 4) and C (5, 11) have x coordinates of 3 and 5 respectively. That x difference is 5-3 = 2 units The given ratio is 2:3 which means we'll have a total of 2+3 = 5 parts Split that 2 unit gap into 5 parts to get 2/5 = 0.4 ------------------------------------------------------ The y difference is 11 - 4 = 7 Split that gap into 5 pieces to get 7/5 = 1.4 ------------------------------------------------------ Because the first number of the ratio is 2, we will move 2 increments in both the x and y directions (starting from point A) so this means x = 3 ----> 3 + 2*(0.4) = 3.8 y = 4 ----> 4 + 2*(1.4) = 6.8 meaning that point B is at (3.8, 6.8) See attached to have a look at what I'm describing
so the answer is A right
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