27. A photon having energy E0 = 0.880 MeV is scattered by a free electron initially at rest such that the scattering angle of the scattered electron is equal to that of the scattered
photon as shown in Figure P40.27. (a) Determine the scattering angle of the photon and the electron. (b) Determine the energy and momentum of the scattered photon. (c) Determine the kinetic energy and momentum of the scattered electron.

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roadjester · Answer

attachment

roadjester · Answer

@douglaswinslowcooper 
@broken_symmetry

roadjester · Answer

@agent0smith

roadjester · Answer

@JoannaBlackwelder 
@KingGeorge 
@wolfe8

wolfe8 · Answer

I know we will use the conservation of momentum and energy in this, but I'm still trying to figure out if we just need some simple way to find the angles since they are equal. Do they add up to 90?

roadjester · Answer

Where did you get 90 from?

wolfe8 · Answer

I was wondering if the total angles will be 90 since I don't think you can disperse 2 objects to a wider total angle from a head on collision. Might be wrong.

roadjester · Answer

umm according to my answers
$$\large \theta =43  $$ in degres

wolfe8 · Answer

Hmm that sounds more probable.