Mathematics
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OpenStudy (anonymous):
A Ferris wheel car moves from point C to point D on the circle shown below:
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OpenStudy (anonymous):
OpenStudy (anonymous):
What is the arc length the car traveled, to the nearest hundredth? (5 points)
Select one:
a. 2.18 feet
b. 4.31 feet
c. 5.84 feet
d. 6.63 feet
OpenStudy (***[isuru]***):
do u know about the equation
\[S = r \theta \]?
OpenStudy (anonymous):
yes now i do
OpenStudy (***[isuru]***):
u can use and find the length of the arc..
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OpenStudy (***[isuru]***):
but to use it the angle theta must be in radiants...do u know about the angles measured in radiants ? i mean not degrees
OpenStudy (anonymous):
yes i do
OpenStudy (***[isuru]***):
so.. ur first step.
convert 38 degrees to radiants
OpenStudy (***[isuru]***):
hint:
\[\pi \ \ rad = 180^{0}\]\[1^{0} = \frac{ \pi }{ 180 }\]
OpenStudy (***[isuru]***):
so... 38 degrees will be ?
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OpenStudy (anonymous):
where do i plug 38 into?
OpenStudy (***[isuru]***):
\[38^{o} = \frac{ \pi }{ 180 }\times 38 \ rad \]
got it ?
OpenStudy (anonymous):
i got it
OpenStudy (***[isuru]***):
so ...
now u have to find the radius r .... the question has given u the diameter..
diameter = 2 x radius
radius = ?
OpenStudy (anonymous):
im not sure i tried to plug it in and a weird decimal came up
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OpenStudy (***[isuru]***):
srry.. u mean the radius ? OR
did u find the radius and plug the whole set of values to S = r theta ?
OpenStudy (anonymous):
im talking about the radius thing
OpenStudy (***[isuru]***):
the given diameter is 20 ft
the diameter equal two times the radius
so.. the radius = diameter /2
OpenStudy (anonymous):
whats the diameter
OpenStudy (anonymous):
ohhh duuhh...
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OpenStudy (anonymous):
so 20/2
OpenStudy (***[isuru]***):
|dw:1392469874068:dw|
OpenStudy (anonymous):
radius =10
OpenStudy (***[isuru]***):
diameter is the chord that passes through the center
OpenStudy (anonymous):
i know is the radius 10
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OpenStudy (***[isuru]***):
yes
OpenStudy (anonymous):
so whats the next step
OpenStudy (***[isuru]***):
now can u plug the values to the equation ?
OpenStudy (***[isuru]***):
\[S = r \ \ \theta\]
OpenStudy (anonymous):
yes i can whats the equation
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OpenStudy (anonymous):
what is that 0 thing and what does S =
OpenStudy (***[isuru]***):
S = the length of the arc ( the distance from C to D )
\[\theta = \ the \ \angle \ what \ \ we \ just \ convert \ \ \to \ radiants \]
OpenStudy (anonymous):
ok what is teh equation supposed to look like
OpenStudy (***[isuru]***):
what do mean by "what is the equation supposed to look like " ?
OpenStudy (***[isuru]***):
\[S = r \ \theta \]is the equation ..
i explained u the terms..
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OpenStudy (anonymous):
i know i mean when we plugged in everything
OpenStudy (anonymous):
can we cancel out anything right now
OpenStudy (***[isuru]***):
\[S = \frac{ \pi }{ 180}\times 38 \times 10\]
OpenStudy (anonymous):
yes its d
OpenStudy (anonymous):
AM I CORRECT!!":)
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OpenStudy (***[isuru]***):
yep exactly !
OpenStudy (anonymous):
thanks for ecplaining so much can i have a medal pleeease:)
OpenStudy (***[isuru]***):
lol... u r welcome! :)