Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

A Ferris wheel car moves from point C to point D on the circle shown below:

OpenStudy (anonymous):

OpenStudy (anonymous):

What is the arc length the car traveled, to the nearest hundredth? (5 points) Select one: a. 2.18 feet b. 4.31 feet c. 5.84 feet d. 6.63 feet

OpenStudy (***[isuru]***):

do u know about the equation \[S = r \theta \]?

OpenStudy (anonymous):

yes now i do

OpenStudy (***[isuru]***):

u can use and find the length of the arc..

OpenStudy (***[isuru]***):

but to use it the angle theta must be in radiants...do u know about the angles measured in radiants ? i mean not degrees

OpenStudy (anonymous):

yes i do

OpenStudy (***[isuru]***):

so.. ur first step. convert 38 degrees to radiants

OpenStudy (***[isuru]***):

hint: \[\pi \ \ rad = 180^{0}\]\[1^{0} = \frac{ \pi }{ 180 }\]

OpenStudy (***[isuru]***):

so... 38 degrees will be ?

OpenStudy (anonymous):

where do i plug 38 into?

OpenStudy (***[isuru]***):

\[38^{o} = \frac{ \pi }{ 180 }\times 38 \ rad \] got it ?

OpenStudy (anonymous):

i got it

OpenStudy (***[isuru]***):

so ... now u have to find the radius r .... the question has given u the diameter.. diameter = 2 x radius radius = ?

OpenStudy (anonymous):

im not sure i tried to plug it in and a weird decimal came up

OpenStudy (***[isuru]***):

srry.. u mean the radius ? OR did u find the radius and plug the whole set of values to S = r theta ?

OpenStudy (anonymous):

im talking about the radius thing

OpenStudy (***[isuru]***):

the given diameter is 20 ft the diameter equal two times the radius so.. the radius = diameter /2

OpenStudy (anonymous):

whats the diameter

OpenStudy (anonymous):

ohhh duuhh...

OpenStudy (anonymous):

so 20/2

OpenStudy (***[isuru]***):

|dw:1392469874068:dw|

OpenStudy (anonymous):

radius =10

OpenStudy (***[isuru]***):

diameter is the chord that passes through the center

OpenStudy (anonymous):

i know is the radius 10

OpenStudy (***[isuru]***):

yes

OpenStudy (anonymous):

so whats the next step

OpenStudy (***[isuru]***):

now can u plug the values to the equation ?

OpenStudy (***[isuru]***):

\[S = r \ \ \theta\]

OpenStudy (anonymous):

yes i can whats the equation

OpenStudy (anonymous):

what is that 0 thing and what does S =

OpenStudy (***[isuru]***):

S = the length of the arc ( the distance from C to D ) \[\theta = \ the \ \angle \ what \ \ we \ just \ convert \ \ \to \ radiants \]

OpenStudy (anonymous):

ok what is teh equation supposed to look like

OpenStudy (***[isuru]***):

what do mean by "what is the equation supposed to look like " ?

OpenStudy (***[isuru]***):

\[S = r \ \theta \]is the equation .. i explained u the terms..

OpenStudy (anonymous):

i know i mean when we plugged in everything

OpenStudy (anonymous):

can we cancel out anything right now

OpenStudy (***[isuru]***):

\[S = \frac{ \pi }{ 180}\times 38 \times 10\]

OpenStudy (anonymous):

yes its d

OpenStudy (anonymous):

AM I CORRECT!!":)

OpenStudy (***[isuru]***):

yep exactly !

OpenStudy (anonymous):

thanks for ecplaining so much can i have a medal pleeease:)

OpenStudy (***[isuru]***):

lol... u r welcome! :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!