Question

Two objects are moving along separate linear paths where each path is described by postion, d, and time, t. The variable d is measured in meters and the variable t is measured in seconds. The equation describing the graph of the postion of the first object with respect to time is d=2.5t+2.2. The graph of the the position of the second object is a parallel line passing through (t=0,d=1). What is the equation of the second graph.

d=2.5t+1
d=-0.4t+1
d=2.5t+3.2

Answer 1

it would have to have the same slope since it is parallel

Answer 2

d=-0.4t+1

Answer 3

and it passes through the point (1,0)

Answer 4

no dude it has the same slope

Answer 5

it would be 2.5

Answer 6

not -0.4

Answer 7

the equation of a line in slope intercept form is

y=mx+b, where m is the slope
& b is the y-intercept (the value when x is zero)

Answer 8

in this equation
d is like y
& t is like x

Answer 9

@binks can you tell me the slope of

d=2.5t+2.2 ?

Answer 10

2.5

Answer 11

im confused how you find the equation

Answer 12

yeah 2.5 is the right slope,

parallel lines have the same slope

so this rules out one of the options

Answer 13

the other piece of information in the question says that when t=0, d=1

so if we plug in these d=2.5t+b

becomes 1=2.5(0)+b

solve this for b

Answer 14

b=1

Answer 15

yeah so you have found
the slope to be m=2.5
& the y-intercept to be b=1

d=2.5t+1

Answer 16

understand?

Answer 17

thank you!!!