I think, there should be a small mistake in the worked example(Session 69).

Integral of (cos(2x))^2 can not be equal x/2 +sin(2x)/4 + c

It must be x/2 +sin(4x)/8 + c

And so the total answer is x/16 - sin(4x)/64 - ((sin(2x))^3)/48 + c
Am I right?!

Question

I think, there should be a small mistake in the worked example(Session 69).

Integral of (cos(2x))^2 can not be equal x/2 +sin(2x)/4 + c 

It must be x/2 +sin(4x)/8 + c

And so the total answer is  x/16 - sin(4x)/64 - ((sin(2x))^3)/48 + c
Am I right?!

anonymous · Answer

I don't have time right now to confirm that your final answer is correct, but I can confirm that you've correctly identified an error in the materials, where they have the formula for the integral of (cos(x))^2 where it should be the integral of (cos(2x))^2.