Mathematics
18 Online
OpenStudy (anonymous):
For the function of f and g, find the following and state the domain of each result
f(x) = 5x+2/3x-4 ; g(x)= 2x/3x-4. How do I solve this pls...
Join the QuestionCove community and study together with friends!
Sign Up
jhonyy9 (jhonyy9):
first of all when is a fraction undefined ?
OpenStudy (anonymous):
when the denominator is equal to zero i think
jhonyy9 (jhonyy9):
yes right so than this will be the first you need calculi for what value will be the denominator zero
ok ?
jhonyy9 (jhonyy9):
so what will be the restriction of x ?
OpenStudy (anonymous):
3x-4 = 0
3x = 4
x=4/3
is this right?
Join the QuestionCove community and study together with friends!
Sign Up
jhonyy9 (jhonyy9):
yes
OpenStudy (anonymous):
what is the restriction on x? x is not equal to 0?
jhonyy9 (jhonyy9):
x not equal 4/3 never because than these fractions will be undefined
yes ?
jhonyy9 (jhonyy9):
because x=4/3 result denominator equal zero
jhonyy9 (jhonyy9):
ok ?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so what is the domain for f(x)?
jhonyy9 (jhonyy9):
moment
now you need make f(x) equal zero and g(x)=0
and calculi
ok ?
OpenStudy (anonymous):
ok working on it....
jhonyy9 (jhonyy9):
try calculi you here ,ok ?
jhonyy9 (jhonyy9):
courage please i will help you
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so will it be 5(4/3) + 2 divided by 3(4/3) - 4 = 0? is this right?
OpenStudy (anonymous):
i got 7/-1
jhonyy9 (jhonyy9):
5x+2
------ = 0
3x-4
5x+2=0
5x=-2
x= -2/5
how you have got this result ?
OpenStudy (anonymous):
I plugged in 4/3 for x. guess i was wrong.
jhonyy9 (jhonyy9):
x=4/3 is a restriction of x
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok so we exclude that right?
jhonyy9 (jhonyy9):
yes sure
OpenStudy (anonymous):
ok am solving for g(x)
jhonyy9 (jhonyy9):
let s go but here ok ?
OpenStudy (anonymous):
2x=0
x=-2
Join the QuestionCove community and study together with friends!
Sign Up
jhonyy9 (jhonyy9):
2x=0
so try prove it for x=-2
you will get zero ?
i think never
jhonyy9 (jhonyy9):
how you have got this -2 ?
jhonyy9 (jhonyy9):
so there is 2x=0 divide both sides by 2
what will get ?
jhonyy9 (jhonyy9):
are you here ?
OpenStudy (anonymous):
sorry... 2x=0
x = 0
Join the QuestionCove community and study together with friends!
Sign Up
jhonyy9 (jhonyy9):
yes sure
this is easy
yes ?
OpenStudy (anonymous):
yayyy got it!... with your help yes it was easy..
now how to write the domain...
jhonyy9 (jhonyy9):
so how you know it where is defined a function f(x) or g(x) so when these are fractions ?
jhonyy9 (jhonyy9):
do you have learned it in your school,yes ?
OpenStudy (anonymous):
yes but online and it is so confusing to follow
Join the QuestionCove community and study together with friends!
Sign Up
jhonyy9 (jhonyy9):
are defined in R without this restriction
what mean R ?
OpenStudy (anonymous):
what is R?
jhonyy9 (jhonyy9):
you dont know it ?
OpenStudy (anonymous):
no.
jhonyy9 (jhonyy9):
how you not the set of real numbers ?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok sure the symbol for the set of all real numbers! yes i do
OpenStudy (anonymous):
I usually write it as x|x
jhonyy9 (jhonyy9):
yes so than you know what is the answer on this exercise now ?
OpenStudy (anonymous):
I guess it is the x|x >=4/3 for f(x) and g(x) x|x>= 2
jhonyy9 (jhonyy9):
why ?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
is that wrong? pls correct me
jhonyy9 (jhonyy9):
so the domain will be R without this restriction of x
OpenStudy (anonymous):
so will that be x|x not equal to 4/3?
OpenStudy (anonymous):
hiya Jhonyy9 are you there?
jhonyy9 (jhonyy9):
yes i m here
Join the QuestionCove community and study together with friends!
Sign Up
jhonyy9 (jhonyy9):
the domain is R without 4/3
ok ?
OpenStudy (anonymous):
I got it. thanks so much. You have been very helpful.
jhonyy9 (jhonyy9):
np
was my pleasure
good luck