Question

please help me: if log a(x+61)=3 and a^3= 125 determine 3^ √x+61

Answer 1

solve for a, first
a^3= 125
a^3= 5^3
a = 5

Answer 2

now see the first equation, log a (x+61)=3
put a = 5, get
log5 (x+61) = 3
change into exponent form : as
x+61 = 5^3
x+61 = 125
x = 125 - 61
x = 64

Answer 3

the last, to get the value of 3^ √x+61
subtitute x = 64, get
3^ √64+61
= 3^ √125
= 5

Answer 4

hope that make sense :)

Answer 5

hey thanks

Answer 6

welcome