Question

two circle A and B touch each other externally,PM=15 cm is a tangent to circle with centre Aand QN=13cm is a tangent to a circle with centre B from external points P and Q .if PA=17cm and BQ=12 cm . find the distance between the centres A and B of circles

Answer 1

ITS AN EASY ONE SOLVE IT COMMON GUYS

Answer 2

@ikram

Answer 3

@ganeshie8

Answer 4

the distance between centers of 2 circles
= AC + CB
but
AC = AM (radius)
CB = BN (radius)
so the distance between the centers of 2 circles
= AM + BN
to find AM
use Pythagoras theorem on triangle APM
to find BN use Pythagoras theorem on triangles BNC

can u do that ?

Answer 5

PM^2 + AM^2 = AP^2
AM^2 = AP^2 - PM^2
= 17^2 - 15^2

Answer 6

or BC =BN AND
AC=AM (radii of the circle)

Answer 7

there is something wrong with ur question
BC should be larger than NC

Answer 8

no in exm they had put it like this only

Answer 9

angle BNQ = 90 ( NQ is a tangent )
so triangle BNQ is a right angle triangle
which means
BQ is the hypotenuse...
hypotenuse is the longest side in a triangle
but ur data does not match it ???

Answer 10

AC = 8 cm

Answer 11

BC =5 cm

Answer 12

BC = 5cm
if and only if
BQ = 13 cm
NQ = 12 cm
not the other way around

Answer 13

u oly need to apply Pythagoras nothing more :o