Find the equation in standard form of the hyperbola with vertices at (8, −1) and (0, −1) and foci (9, −1) and (−1, −1).

a.) (x+4)^2/16-(y-1)^2/9=1
b.) (x+4)^2/9-(y-1)^2/16=1
c.) (x-4)^2/9-(y+1)^2/16=1
d.) (x-4)^2/16-(y+1)^2/9=1

Question

Find the equation in standard form of the hyperbola with vertices at (8, −1) and (0, −1) and foci (9, −1) and (−1, −1).
 	
a.) (x+4)^2/16-(y-1)^2/9=1
b.) (x+4)^2/9-(y-1)^2/16=1
c.) (x-4)^2/9-(y+1)^2/16=1
d.) (x-4)^2/16-(y+1)^2/9=1

mertsj · Answer

The center is half way between the vertices so find the center.

mertsj · Answer

What is it?

mathmale · Answer

Mertsj has given you an important hint.  Knowing the center of the hyperbola, you can eliminate two of the four possible answers given.  Mind finding that center?