help please. eh so many questions sorry
Whats going on man?
okay so there are two triangles
k
its asking to find the area of one of them.
@iambatman i need to tawk wid uh
>_>
fan me :@
the smallest triangle kjl and 12 cm and hcm so they dont give me a number for h
SO the smallest triangle is sides K, G, L which sides is 12cm?
f) first use 9/18 = h/12 and then use the area 1/2 (12h) g) 9/18=h/12 and then use area=12h h)9/18=12/h and then use area= 1/2(12h) j)9/18=12/h and then use area = 12h
so its looking for the area of jkl. and 12cm is on the bottom part of the triangle
and the bigger triangles is 9cm and 18 cm
|dw:1392599480619:dw|
not to be a pest or anyting but do you know how to solve it or should i just move on?
Oh you got this one. Area = Base times Height divided by 2
So s,r,t A=81
thank you so much, sorry fo being a pest :)
9*18=162/2=81
not being a pest, i had to run out for a minute to the store and my ride couldn't wait
f) first use 9/18 = h/12 and then use the area 1/2 (12h) g) 9/18=h/12 and then use area=12h h)9/18=12/h and then use area= 1/2(12h) j)9/18=12/h and then use area = 12h these are the answer choices
i don't see what they are wanting for some reason. I can solve for the first one because I have both base and height, but I don't have both on the second one.
alright its fine. ill try to solve it
i think H
Your forumlas for triangles are \[A=\frac{ b * h }{ 2 }\] or\[ A=\frac{ 1 }{ 2 } *b*h\]
ya my teacher last year told me that but everything has been cleared from my brain. so h is pretty much correct?
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