Mathematics
22 Online
OpenStudy (anonymous):
Identify the graph of f(x) = 3|x + 2|.
How would I do this?
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OpenStudy (anonymous):
OpenStudy (anonymous):
Start with \(g(x) = |x|\). That is simple to graph, right?
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
We can see \(g(x+2)=|x+2|\)
OpenStudy (anonymous):
Do you know the relationship between \(g(x)\) and \(g(x+2)\)?
It is a translation.
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OpenStudy (anonymous):
Does it shift the graph up, down, left, or right?
OpenStudy (anonymous):
....up??
OpenStudy (anonymous):
Nope.
OpenStudy (anonymous):
How do I figure out which way it goes?
OpenStudy (anonymous):
Okay well, we know \(g(0) = |0| = 0\). Where does this point go after we translate?
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OpenStudy (anonymous):
On the origin, right?
OpenStudy (anonymous):
Wait, no, nvm..
OpenStudy (anonymous):
Well, we have the point \((0,0)\) but where is it put?
OpenStudy (anonymous):
IDK. :(
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OpenStudy (anonymous):
So... to the right??
OpenStudy (anonymous):
Oh wait, oops, wrong one, to the left.
OpenStudy (anonymous):
Yep, it move to the left 2 units.
OpenStudy (anonymous):
Oh...
OpenStudy (mertsj):
f(x)=x
(x)=(x-2) moved 2 units to the right
f(x)=(x+2) moved 2 units to the left
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OpenStudy (anonymous):
so \(f(x)=3g(x+2)\). You need to figure out how the \(3\) changes the graph.
OpenStudy (anonymous):
Oh, so how do I do that?
OpenStudy (anonymous):
Well, the 3 should stretch the graph upwards.
OpenStudy (anonymous):
Oh, okay, but if it was negative it would make it go down, right?
OpenStudy (anonymous):
I know B and C are out.
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OpenStudy (anonymous):
Yep
OpenStudy (anonymous):
Now, of A and D, which one stretches the graph upward more?
OpenStudy (anonymous):
A
OpenStudy (anonymous):
Nope. Actually A isn't stretched at all.
OpenStudy (anonymous):
It's not?
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OpenStudy (anonymous):
no, if you look at it, the slope is 1 and -1. The slops should have changed to 3 and -3
OpenStudy (anonymous):
the slope changes at the bottom of the V
OpenStudy (anonymous):
Oh okay