What is the value of work done on an object when a 10-newton force moves it 30 meters and the angle between the force and the displacement is 25°?

Question

anonymous · Answer

the effective component of the force that does work is the force in the direction of the displacement.

anonymous · Answer

having this in mind, multiply $$Fcos(\theta)$$ by the displacement

masumanwar · Answer

we have force=10 newton
displacement=30meters and angle 25 degree
we know the formula workdone w=fscostheta
therfore workdone is putting this values 
271.89 joul

anonymous · Answer

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