Question

The equilibrium constant for the reaction of carbon monoxide with water is 1.845. If 1.00 mol of each reactant is placed in a 2.00 L container, what is the concentration of carbon dioxide at equilibrium?
CO(g) + H2O(g) CO2(g) + H2(g)

Answer 1

0.287983 M = 0.288 M

CO + H20 ----> CO2 + H2
I 0.5M 0.5M 0.0 0.0
C -x -x +x +x
E 0.5-x 0.5-x x x

\[Keq = \frac{ [CO _{2}] [H2] }{ [CO] [H _{2} O]} = \frac{ x ^{2} }{ (0.5-x)^{2} }= 1.845\]

calculate the value for x \[x = \frac{ 0.5 \sqrt{1.845} }{ 1+ \sqrt{1.845} } = 0.2879= 0.288 M\]