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Mathematics 21 Online
OpenStudy (anonymous):

How do you evaluate ∫sqrt(lnx)/x dx ?

OpenStudy (anonymous):

let u = lnx du = dx/x you can finish from here

OpenStudy (anonymous):

Alternatively. Let \(x=e^u\) and \(dx = e^udu\).

OpenStudy (anonymous):

I have that part down I just dont know what to do after that

OpenStudy (anonymous):

you got sqrt(u) du yes?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

sqrt(u) = u^(1/2), now use use the power rule

OpenStudy (anonymous):

yes which gives me 1/2u^-1/2

OpenStudy (anonymous):

If \(n=1/2\) then \(n+1=3/2\) and \(1/(n+1) = 2/3\)

OpenStudy (anonymous):

wait, thats the antiderivative , don't we need to find the derivative of u first?

OpenStudy (anonymous):

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