A boy can row a boy at a constant speed of 5 mi/ hr in still water. he rows upstream for 20 minutes then rows downstream for 12 minutes returning at his starting point. Find total distance traveled if rate is 1.25 upstream is 5-x downstream is 5+x
row a boat
Let speed of current = c speed against current (upstream) = 5 - c speed downstream = 5 + c distance traveled = speed x time distance traveled upstream = (1/3)(5 - c) [because 20 min = 1/3 h] distance traveled downstream = (1/5)(5 + c) [because 12 min = 1/5 h] but these distances are the same so (1/3)(5 - c) = (1/5)(5 + c) Multiply both sides by 15 to get rid of the fractions: 5(5 - c) = 3(5 + c) 25 - 5c = 15 + 3c 10 = 8c c = 1.25 mph → so you're right and just about finished Total distance = (1/3)(5 - c) + (1/5)(5 + c) subs for c: = (1/3)(5 - 1.25) + (1/5)(5 + 1.25) = 2.5 mi
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