The change in water level of a lake is modeled by a polynomial function, W(x). Describe how to find the x-intercepts of W(x) and how to construct a rough graph of W(x) so that the Parks Department can predict when there will be no change in the water level. You may create a sample polynomial to be used in your explanations.
@phi do you think you can help me out with this question please i tried but it really hard
@phi do you think you can help me with this question
You may create a sample polynomial to be used in your explanations. I think they want you to make up a polynomial, and then explain how to find where it equals zero.
oh ok
so i had created one \[2x ^{3}+3x ^{2}-x-4\]
i had put one and i had got zero
can you explain what you mean "i had put one and i had got zero "
i had substitute the x with 1 solve the equation and i got zero
oh, ok. that sounds right.
The question asks Describe how to find the x-intercepts of W(x) and how to construct a rough graph of W(x) Did you have a lesson on how to find the x-intercepts of a polynomial ?
no not that i remember
Look through your notes, because they want you to explain how to find the x-intercepts of a polynomial. I don't know what they taught you, so you have to look it up. Also look up the lesson on how to plot polynomials.
i did and its not there
Here is one way http://tutorial.math.lamar.edu/Classes/Alg/FindingZeroesOfPolynomials.aspx use the rational root theorem
and use synthetic division
cant i just use the synthetic division
instead of the rational root theorem
and how would i use the synthetic division for this problem
The rational root theorem gives you the "guesses" that might work. synthetic division is a way to check each of the guesses.
you can use synthetic division to show that x= 1 is a zero. you will get a remainder of zero, which means x=1 is a zero of your function also, the answer will be a quadratic which you can try to find the roots of... (but it won't have any real zeros)
so the formula for the rational root theorem is \[x=\frac{ b }{ c }\]
@phi
this problem is really giving me a headache
the rational root theorem says take the last number (the constant) which is -4 list its factors 1,2,4 <-- call these p then take the number in front of the highest order term (the number in front of x^3) which is 2 list its factors 1,2 <-- call these q list all combinations of ±p/q can you do that ?
yea the factor of 4 is 1*4 2*2
factors of 2 1*2
factor of 1 is 1*1
yes, now list all combinations of 1,2,4 (from the 4) divided by 1 or 2 (from the 2 in front of x^3)
ok i divided it by 2 and got 0
meant 1
in other words take the first number from the list 1,2,4. it is 1 now take the 1st number from the second list of 1,2, it is 1. write down 1/1 = 1 then the second number from the second list, and get ½ that means the possible roots are -1, +1, -½, + ½ next, we take the 2nd number from the first list: the 2, and divide it by 1 and by 2 to get 2 and 1. that means more possible roots: -2, +2, -1, +1 (but we already got the 1's) finally do the 4
you know 1 is the root, so we don't have to test all the choices. But you have to explain a way to find the 1... so we use the rational root theorem to get a list of numbers. then test a few... of course, 1 will work. once you find x=1 works, look at the quotient you got when you did synthetic division
ok i think i got it now
could you help with 1 more last question
please make it a new post.
i already know
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