Question

Identify the oblique asymptote of f(x) = quantity x squared plus 6 x minus 9 over quantity x minus 2

Answer 1

@radar @austinL @Mchilds15 @RioAnne @bluegusta @Cubi-Cal @PurplePanda312

Answer 2

You're asking the wrong person, sorry. Have you tried Wolfram Alpha? It walks you through the problem.

Answer 3

yea

Answer 4

@GABBY2017 @AccessDenied @nepurrta @mary.rojas @tester97 @LegoMyEgo @googlesun

Answer 5

What value of x would result in a division by 0?

Answer 6

i dont know

Answer 7

0?

Answer 8

if x was a 0 you would be dividing by -2 no no
Look at the denominator of your fraction that is the divisor. What value of x would result in a denominator equal to 0 ?

Answer 9

-2?

Answer 10

like this is so confusing

Answer 11

You're thinking but only one little thing is wrong with x =-2
Your denominator with x being a -2 would look like this: -2-2 That would be -4 not a zero, the only part of that, that is wrong is the sign. When x =2 your function will run off the rails and become undefined or asymptote.

Answer 12

2-2 = 0

Answer 13

But you knew that. just didn't want to say it.

Answer 14

ok i see and understand what you are talking about

Answer 15

i am so sorry my computer was acting stupid and i had to switch to another computer

Answer 16

but im still lost i tried solving it but not getting the right answer

Answer 17

here are the answer choices
y = 0

y = x + 8

y = x + 4

No oblique asymptote

Answer 18

@radar

Answer 19

@april115 @googlesun @hlee13 @Partycool @PottedPlant @yamini_malik @triciaal

Answer 20

@heather040200 @mangorox

Answer 21

My bad, i had to look up "oblique" and here is what you do.
You have a fraction where the numerator is exactly one degree higher than the denominator. Here is what you do: