Linear equation (solve by substitution) 16x+19y=82 6x+y=190 This is the step I think of next... -19(6x+y=190)
So you are trying to substitute the second equation into the first?
And I think you made a typo somewhere in your first equation
I am trying to make the y's match up so I can get rid of them (one has to be negative one has to be positive) This way they cancel than I can move on to find y.
Oh ok. Then yes, that would be your next step. I got confused because this method is called elimination, not substitution
My paper says substitution. But from how it is I guess it can be both. Ok well after that step I do this 16x+19y=82 + -114x+-19y=-3610
Correct. And now add them up
-98x=-3610
You forgot to add the right hand side So -98x= -3528 And now solve for x
yeah i just noticed and its 36
Oh my god -_____- I just realized I got it wrong every time because i forgot the other side of the =
Haha, it's ok. So what did you get for y after plugging 36 into x for one of the equations
for y im getting -34.6 but she said there are no decimals or fractions
I don't think you did it right. Try it again. You should get -26
So I have to make it negative by subtracting 576?
This is pluggin into second equation 6(36)+y=190 216+y=190 -216. -216 ---------------- y=-26
Im doing the wrong problem -____- I cannot think today
Or if you were doing the first, 16(36)+19y=82 576+19y=82 -576. -576 ------------------- 19y= -494 --- ----- 19. 19 y=-26
Thank you so much! I feel so retarded.
No problem. Wait till you here this. If you actually follow the directions, substitution would have been much faster. Subtract 6x on both sides in your second equation so you have y= 190-6x Substitute this into the first equation so 16x + 19(190-6x)=82 And now solve for x And then do the same thing as the previous problem to solve for y
-_____- I swear my teacher doesn't give us the right notes with titles and instructions...
Haha. Sounds like you have a great teacher
WONDERFUL!!!
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