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for what values of a and b is the following function continuous at every x?
F(x)= -4 x <= -3
ax-b -3
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this is much easier than it looks replace \(x\) by \(-3\) and set the result equal to \(-4\) then replace \(x\)by \(1\) and set the result equal to \(2\) solve for \(a\) and \(b\)
so your saying set a(-3)-b = -4?
ohh okay you mean set the x in f(x)= -4 and then =2
\[-3a-b=-4\\ a-b=2\]
i.e. \[a\times (-3)-b=-4\\ a(1)-b=2\]
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then solve the system \[-3a-b=-4\\ a-b=2\] for \(a\) and \(b\)
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