Question

A hoop rolls down an inclined plane. What fraction of its total KE is associated with its rotation? I=mr^2

Answer 1

for a hoop k.Erot = 1/2 mv^2
u know how ???

Answer 2

i don't

Answer 3

K.E =1/2 Iw^2
I for hoop is mr^2
So
K.E = mr^2w^2
r^2w^2 = v^2
K.E = 1/2 mv^2


w = omega Angular velocity
I = moment of Inertia