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Mathematics 25 Online
OpenStudy (anonymous):

Factorize -3(x-2y) + 6(x-2y)^2

ganeshie8 (ganeshie8):

is there a GCF ? start by pulling out the GCF

ganeshie8 (ganeshie8):

\(\large -3(x-2y) + 6(x-2y)^2\)

ganeshie8 (ganeshie8):

see that both terms, have \(3(x-2y)\) as common, so factor it out first

ganeshie8 (ganeshie8):

\(\large -3(x-2y) + 6(x-2y)^2 \) Factoring out GCF gives : \(\large 3(x-2y)[-1 + 2(x-2y)] \)

ganeshie8 (ganeshie8):

simplify the thing inside right 'square brackets'

OpenStudy (anonymous):

the basic way if you're confused, is to expand it first, then factorise the equation as a whole -3(x-2y)+6(x-2y)^2 =-3x+6y+6(x^2-2xy+4y^2) remove brackets, simplify and factorise

OpenStudy (anonymous):

anwers= -3(x-2y)(4y+1-2x)

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