Question

Lim. 3t^2-7t++2/2-t
X→2.

Answer 1

is this x->2 or t->2

Answer 2

can u factorize the numerator ?

Answer 3

Yes I did

Answer 4

(x-2)(x-1/3)/2-t

Answer 5

I canceled out the t-2) and got left with (x-1/3) I pluged to in back to it.

Answer 6

if u use L' Hospital rule,
differentiate both numerator and denominator

Answer 7

hmmm ... you question doesnt seem to be clear.. r u trying to find the limit of
\[\lim_{t \rightarrow 2}\frac{ 3t^{2} -7t + 2 }{ 2 -t }\]??

Answer 8

yes... thats what it is.

Answer 9

I couldn't find how to do that.

Answer 10

ans is -5

Answer 11

I got 5/3

Answer 12

\[\lim_{t \rightarrow 2}\frac{ (2 -t)(1 - 3t) }{ (2-t) }\]\[\lim_{t \rightarrow 2} (1-3t)\]

Answer 13

now plug 2 to ( 1 - 3t) thats the limit you want...

Answer 14

Wait shouldn't it be a ffraction?

Answer 15

which is -5... i think you made your mistake when you factorize the numerator... try to do it again sometime..:)

Answer 16

u can cancel out ( 2-t) from numerator and denominator.....so... the fraction is no more

Answer 17

I did the slide and divide method

Answer 18

are u know 0/0 form of limit
when a limit get in to 0/0 form after put the x->2 value
then L 'Hospital rule is apply ,

Answer 19

So I divided it by 3 so I should get 1/3

Answer 20

OH, THAT is what I forgot.

Answer 21

It's 1/(1/3)

Answer 22

Wait.. no it's not.

Answer 23

if u use slide and divide....
u divide 3t^2 by 3 which will get t^2
then u should multiply if by the constande which is 2x3 = 6
so...
u will get
t^2 -7t + 6
did u come up to here ?

Answer 24

Plz see this


http://tutorial.math.lamar.edu/Classes/CalcI/LHospitalsRule.aspx

Answer 25

^ you aren't helping Jaga.. I've already been to that website. Thank you though.

Answer 26

Yes. I've gotten up to that point.

Answer 27

Then I did (x-6)(x-1)

Answer 28

I divided both by 3 so I ended up with (x-2)(x-1/3)

Answer 29

are you know differentiation the u can use L hospital rule
limit(3t^2-7t+2)/(2-t)
t->2

put 2 in the limit
then u got 0/0 form

then differentiate both numerator and denominator one time then u got

limt(6t-7)/(-1)
t->2

then u put 2 in the limit

then u got -5

Answer 30

u have forgot the last rule of slide and divide...

Answer 31

Once it’s simplified, if there’s a fraction left, the denominator becomes the coefficient of the variable term.
ANSWER: (x-2)(x-1/3)
( x-2) (3x - 1)

Answer 32

now u can get the same answer :)