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Triangle STU is located at S (2, 1), T (2, 3), and U (0, -1). The triangle is then transformed using the rule (x-4, y+3) to form the image S'T'U'. What are the new coordinates of S', T,' and U'?
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Just subtract 4 from each of the x components and add 3 to each of the y components.
I tried that, but it came out so weird. Like it wasn't equal or something? I know where S and T are placed, but U I'm not sure of, I even subtracted 4 and added 3.
I got (-2, 4) for S' and T' was (-2,6)
\(S(2,1)\longrightarrow S(x_s,y_s)\) So from this, \(S_{rule}=(x_s-4,y_s+3)=((2)-4,(1)+3)=(-2,4)\) You just go from there. For \(U(0,-1)\) \(U_{rule}=(x_u-4,y_u+3)=((0)-4,(-1+3))=~?\)
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