Question

The area of a rectangle is 65m^2, and the length of the rectangle is 3m less than twice the width. Find the dimensions of the rectangle.

Answer 1

@tester97 try this lol

Answer 2

@Euler271 dude... just in time.

Answer 3

lol hey

Answer 4

so area is L * W = length * width

the equation says L = 2W - 3 (3 less than twice the width)

so L * W = 65

plug in L = 2W - 3

(2W - 3) * W = 65

solve for W

Answer 5

-5, 13/2

Answer 6

yes. and since -5 doesn't make sense, we know the answer is W = 13/2

you can plug that W into L = 2W - 3 to find L

Answer 7

l=2(13/2)-3?
l=10? :3

Answer 8

yes

Answer 9

i was about to make food. ill be on later. im working from home today :P

Answer 10

lol

Answer 11

up to you. sometimes latex is useful

Answer 12

wanna try it out? i'll tell you if you're doing it right

Answer 13

latex? o.o

I got the answer for that one already

Answer 14

\[\sqrt{this\ is\ latex}\]

Answer 15

Oh, I got it.
The length of a rectangle is 5ft less than three times the width, and the area of the rectangle is 50ft^2. Find the dimensions of the rectangle.

L*W
L*W=50
L=5w-3
(5w-3)*W=50
W=3/5 +10/w...? what.

Answer 16

actually 5 less than 3 times is 3w - 5

Answer 17

afk making food though

Answer 18

(3w-5)*w=50?

Answer 19

-10/3, 5

Answer 20

yes