Question

Algebra 2 help?

Answer 1

\[9=\sqrt{27}^{4x+6}\]

Answer 2

Hint : when
\[a^{n} = a^{m}\]
then n = m

Answer 3

I don't understand

Answer 4

is it 9 = sqrt {27^(4x+6)}?????

Answer 5

Yes

Answer 6

@undeadknight26 help?

Answer 7

can we write
3^2 = sqrt { 3^3(4x+6) }
3^2 = 3^3(4x+6)/2
as the base is same
therefore , we can write
2 = 3(4x+6)/2
hope u understand this problem now

Answer 8

I have no idea what you did can you explain it please

Answer 9

seems i have to explain it step by step

Answer 10

in first step
i have written 9 as a square of (3)
can 27 be written as cube of (3)?

Answer 11

Yes because 3^3 = 27

Answer 12

so i did that in first step
did u understand it?

Answer 13

How do I write that though

Answer 14

in a second step
can we write \[\sqrt{x} = x^{\frac{ 1 }{ 2 }} ????\]

Answer 15

i think i m not able to explain it you in a better way
@radar will be more helpful to you

Answer 16

I'm just really confused. :(

Answer 17

@radar can you help

Answer 18

I can try, but niksva was doing an excellent job.

Answer 19

I thought so too I just need someone to explain to to me :(