How do you graph y=logbase6(x-1)-5? Please explain the steps to graphing the logarithm.
pick a few random "x", get their "y" plot them
How would I input the x and solve for it if the equation has a log? Do I turn it into exponential form and solve it then? And if I do, what would be the exponential form of the log? Can you provide an example with x=1?
hmmm
well, I gather you're just trying to graph \(\bf log_6(x-1)-5\) you wouldn't need to make it exponential, just use that as is, your calculator would have a [log] button you could use
you could just turn it into a log base 10 for the calculator \(\bf \textit{change of base rule of } {\color{blue}{ log_ab\implies \cfrac{log_cb}{log_ca}}}\\ \quad \\ log_6(x-1)-5\implies \cfrac{log_{10}(x-1)}{log_{10}6}-5\)
From the change of base version, how would I plug in a number for x and come out with points? Apparently one of the points is (1,-7) and I'm not sure how I'd plug in 1 in x and come out with -7.
hmm
well.. it can't be 1, -7, that makes x = 1... which gives the value for the log to 0 and logarithm values have to be greater than 0
I think that point is on the asymptote. I think the better point to plug in would be (2,-5) which is still on the line, but I don't know how to plug in the x and solve for the y.
use the [log] button in your calculator, do you have one? you can always just use www.desmos.com/calculator
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