Question

Simplify the complex fraction.

Answer 1

404 fraction not found

Answer 2

OS crashed for me for a moment!

Answer 3

Your first step is to simplify the middle terms if possible. You should be able to put them into two binomials.

\[\frac{ n-6 }{ (n + 8)(n + 3)} * \frac{ n + 3 }{n + 1 }\]

Answer 4

You see, since the bottom fraction is being divided by the upper fraction, I can simply reverse the fraction and it becomes multiplication. Now I can just cancel terms and multiply. get it?

Answer 5

Kinda. Can you show me?

Answer 6

Well, we know n + 3 and n + 3 will cancel, right?

So we have \[\frac{ n + 6 }{ n + 8} * \frac{ 1 }{ n+ 1 }\]

From here we can simply cross multiply. An example would be:

x
-----
y
------------
c + 1
--------
b

I could solve this fraction by inverse (c + 1/b) because, as I am sure you already know, dividing is the same thing as multiply by the inverse.

x/2 = x * (1/2)
[ x divded by two is equal to x times the inverse of 2 (1/2)]

So when you get problems like this, simplify and cross multiply if possible, then invert the bottom fraction so you can cancel and cross multiply.

Answer 7

Can you finish it?

Answer 8

n-6
---------
(n+1)(n+8)

Answer 9

thanks for explaining :)

Answer 10

\[\frac{ n - 6 }{ n + 8 } * \frac{ 1 }{ n + 1 }\]

You might want to check your answer. CROSS multiply. :)

Answer 11

\[\frac{ n + 5 }{ n + 8}\]

Answer 12

(;

Answer 13

I was right :~)

Answer 14

Hmm. That's odd. Did you cross-multiply? Your n + 1 * n - 6 = n - 6+....

Oh, I see, the denominators go together and I canceled them. Good eye (;