Physics
19 Online
OpenStudy (anonymous):
Attached !
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OpenStudy (destinymasha):
where!
OpenStudy (anonymous):
OpenStudy (anonymous):
Here it is !!
OpenStudy (roadjester):
lol
OpenStudy (destinymasha):
lol
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OpenStudy (anonymous):
Its not B
OpenStudy (roadjester):
\[\huge\vec F = G {m_1m_2 \over r^2}\hat r\]
OpenStudy (anonymous):
Im not sure I tried B so i know its not B
OpenStudy (roadjester):
I'd honestly say C
OpenStudy (destinymasha):
im honestly not sure -- so you might wanna go with his answer?
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OpenStudy (anonymous):
Im torn in between A and C
OpenStudy (destinymasha):
im thinking c --now that you think about it :}
OpenStudy (roadjester):
Think of it this way.
OpenStudy (destinymasha):
A is getting closer......
OpenStudy (anonymous):
It told me that the larger the object the stronger the gravitational force
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OpenStudy (roadjester):
You want a location in which the gravitational force is closest to 0.
OpenStudy (destinymasha):
so where there is almost none?
OpenStudy (destinymasha):
yea -C
OpenStudy (roadjester):
if you were to place a mass closer to the moon, then it would "neutralize" the overall force
OpenStudy (roadjester):
if that makes sense...
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OpenStudy (destinymasha):
a bit :}
OpenStudy (roadjester):
|dw:1392776799133:dw|
OpenStudy (anonymous):
I was thinking C . What you are saying makes sense
OpenStudy (destinymasha):
yes it does :}
OpenStudy (roadjester):
lol; already taking modern physics and yet I have trouble explaining this stuff...
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OpenStudy (destinymasha):
lol
OpenStudy (anonymous):
|dw:1392776997641:dw|