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OpenStudy (anonymous):
\[ \sin^{-1} 1=x\]
OpenStudy (anonymous):
do you know a number \(\theta\) with \(\sin(\theta)=1\) ?
OpenStudy (anonymous):
No is that when sinx=1?
OpenStudy (anonymous):
yes, you are looking for the \(x\) where \(\sin(x)=1\)
OpenStudy (anonymous):
How do I do that?
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OpenStudy (anonymous):
i guess you are just supposed to know it
look at the unit circle on the last page of the attached cheat sheet
you will see where the second coordinate on the unit circle (that is sine) is 1
OpenStudy (anonymous):
look right up top on the unit circle
let me know if you see what i am referring to
OpenStudy (anonymous):
I see it. So how do I plug what I have into it?
OpenStudy (anonymous):
you see right on top of the unit circle is the point \((0,1)\) right?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
the corresponding angle in radians is \(\frac{\pi}{2}\) and in degrees is 90
that means \(\sin(\frac{\pi}{2})=1\)
OpenStudy (anonymous):
and that means \(\sin^{-1}(1)=\frac{\pi}{2}\)
you don't plug it in to anything
you just look for it