Question

please help!!

Which of the following functions has the same asymptotes as y = cotx?



y = cscx

y = secx

y = tanx

y = -tanx

Answer 1

cot x is 1/tan x, therefore the asymptotes are the same when draw in the same graph as y=-tanx @mathmale can you check this and maybe explain why please

Answer 2

i thought it was -tanx too! but i got the question wrong ):

Answer 3

What I'd try first would be to write cot x as
cos x
cot x = -------
sin x

Answer 4

Any asymptootes of cot x would be zeros of sin x.

Care to experiment with that?

Answer 5

then it would be 1/tan!

Answer 6

Hint: csc x = 1/(sin x)

Answer 7

ummm y=secx?

Answer 8

\[\cot (x) = \frac{ \cos(x) }{ \sin(x) }\] so it has asymptotes wherever sin(x) = 0.
What function is the inverse of sin(x)? That will be your answer :)

Answer 9

the inverse function would be csc (x) cause its 1/sin(x)?!

Answer 10

yep!

Answer 11

thank you tons!

Answer 12

u r welcome!

Answer 13

Note: in "the inverse function would be csc (x) cause its 1/sin(x)"
the proper term is "reciprocal," not inverse.

The reciprocal of the sine function is the cosecant function.
The inverse of the sine function is \[\sin ^{-1}x\], which is very different from the reciprocal.

Thought you might want to know this.