Help and i will give THE BEST RESPONSE a metal . . . Greg drew a square with each side equal to z units Part A: Greg increased the length and width of the square by t units each. What will be the change in the area of the original figure? show your work Part B: the same thing as a but you are decreasing by t and show your work Part C: increased the length by t and decreased the width be t
wat is T?
First the square is \(z\) by \(z\). Area of a square = \(s^2\) where \(s\) is the side length, so the area of the initial square is \(A=z^2\). If he increases the sides to \(s=z+t\) the area changes to \(A=(z+t)^2 = z^2+2zt + t^2\) Subtract the area of the original square to find the increase. That should give you enough to go on.
Area of the figure in part C will be \[A = l*w\]where \(l\) is the length and \(w\) the width
thx @whpalmer4
T is a variable representing what he added or subtracted from the length and width @theonlycool13
You're welcome!
Oh ok
duh
Join our real-time social learning platform and learn together with your friends!