Question

40C10

Answer 1

can someone help me solve this

Answer 2

\[{}_{40}C_{10}=\frac{40!}{10!(40-10!)}=\frac{40!}{10!30!}=\frac{40\times39\times\cdots\times32\times31}{10\times9\times\cdots\times2\times1}\]

Answer 3

Notice that parts of the denominator will disappear if you divide through. For example, there's a 36 somewhere in the \(\cdots\) section of the numerator, which is divisible by 9, leaving you with 4. Do the same with as many numbers as there are in the denominator.

Answer 4

thank you so much i get it now