Question

Use the product rule to find derivative
y=(7x-6)^2

Answer 1

\(\bf y=(7x-6)^2\implies y=(7x-6)(7x-6)\\ \quad \\
\cfrac{d}{dx}[(7x-6)]\cdot (7x-6)+(7x-6)\cdot \cfrac{d}{dx}[(7x-6)]\)

Answer 2

i got 182x^2 as answer

Answer 3

why in gods name would you do that.

Answer 4

heheh

Answer 5

after that step that you did..i did (7x-0)(7x-0)

Answer 6

\(\bf \cfrac{d}{dx}[7x]\implies 7\cdot 1x^{1-1}\)

Answer 7

wait is it 98x^2+84x

Answer 8

ahemm.... close

Answer 9

\(\bf \cfrac{d}{dx}[7x]\implies 7\cdot 1x^{1-1}\implies 7x^0\implies 7\)

Answer 10

98x^2+84

Answer 11

98\(\large\bf x\)+84

Answer 12

well. dohhh ahemm -84 rather

Answer 13

check your distribution

Answer 14

wait so whats the answer

Answer 15

well... what's the derivative of (7x -6) ?

Answer 16

y=49x^2+42+49x^2+42

Answer 17

\(\bf y=(7x-6)^2\implies y=(7x-6)(7x-6)\\ \quad \\
{\color{blue}{ \cfrac{d}{dx}[(7x-6)]}}\cdot (7x-6)+(7x-6)\cdot {\color{blue}{ \cfrac{d}{dx}[(7x-6)]}}\\ \quad \\

{\color{green}{ \cfrac{d}{dx}[7x-6]\implies 7\cdot 1x^{1-1}-0\implies 7x^0\implies 7}}\qquad thus\\ \quad \\

{\color{blue}{ 7}}\cdot (7x-6)+(7x-6)\cdot {\color{blue}{7}}\)

Answer 18

\[y=98x^2-0\]

Answer 19

@jdoe0001

Answer 20

hmm recheck your distribution

Answer 21

omg i dont know what im doing wrong

Answer 22

\(\bf {\color{blue}{ 7}}\cdot (7x-6){\huge +}(7x-6)\cdot {\color{blue}{7}}\)

Answer 23

49x-42+49x-42

Answer 24

yeap