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Mathematics 14 Online
OpenStudy (anonymous):

use the product rule to find the derivative g(t)=(3t^2)^2

OpenStudy (kainui):

Are you sure you wouldn't rather use the power rule?

OpenStudy (anonymous):

im sure

OpenStudy (kainui):

\[g(t)=(3t*t)*(3t*t)\] So to use the product rule we should probably rewrite it like this, then our derivative will start to look like this: \[g'(t)=(3t*t)'*(3t*t)+(3t*t)*(3t*t)'\] but if you use the power rule it'll be more like: g(t)=9t^4 g'(t)=36t^3

OpenStudy (anonymous):

\[g(t)=(3t^2)^2\]

OpenStudy (anonymous):

opps i wrote it wrong

OpenStudy (anonymous):

\[g(x)=(3x^2+2)^2\]

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