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Find the magnitude and direction of the vector. Round the length to the nearest tenth and degree to the nearest unit. The diagram is not drawn to scale.
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you can use pythagorean theorem to find the length (magnitude)
A^2 + B^2 = C^2 4^2 + 6^2 = C^2 16 + 36 = C^2 C^2 = 52 is that correct @phi
yes. but the length C is sqr(52) or 2 sqr(13)
do you know how to find the angle? I would use inverse tan tan A = opposite/adjacent
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To be honest i don't know how to find tan at all!
have you learnt it at all? otherwise there might be another way to solve the Q without using trig. |dw:1392990509028:dw| also, is this physics or math
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