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Mathematics
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Graph the function
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\[x ^{2} + 2x - 3\] draw chart to show at least three ordered pairs that are on the graph
Go on wolfram alpha to check the chart http://www.wolframalpha.com/input/?i=x^2+%2B+2x+-3
Then plot the points, any points you want. For the x value of 0: f(0) = 0^2 + 2(0) -3 = -3 f(1) = 1^2 + 2(1) -3 = 0 f(2) = 4 + 8 - 3 = 9 f(3) = 9 + 6 - 3 = 12 Does this make sense?
Yeah. but how..what r the points. id graph
Okay. Well the first x value is 0, and I found out that the y value is -3 (0,-3) When I put x = 1 into the equation, I got y = 0 (1,0) Do you see the pattern. With any given x value, you can find the corresponding y value
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