Hiii, do you think you could help me on this problem? :P
A 20-ohm resistor is connected to four 1.6v batteries. What is the joule heat loss per minute in the resistor if the batteries are connected (a) in series and (b) in parallel?

Question

Hiii, do you think you could help me on this problem? :P
A 20-ohm resistor is connected to four 1.6v batteries. What is the joule heat loss per minute in the resistor if the batteries are connected (a) in series and (b) in parallel?

anonymous · Answer

@wolfe8

wolfe8 · Answer

Well, do you know how to add voltages in parallel and in series?

roadjester · Answer

Power in Watts = Joules/s
so J=Ws

roadjester · Answer

$$\large P={V^2\over R}$$

roadjester · Answer

now just add your batteries and substitute

anonymous · Answer

Did: (1.6x4)^2/20 = 2.048J/min... doesn't seem right? @roadjester

roadjester · Answer

just a minor correction; the math is right but Watts are J/s; next you need to multiply by 60